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ZOJ 3768 Continuous Login

2014 浙大校赛 B

其实就是找到规律最多只可能是1,2,3种分割

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/* From: Lich_Amnesia
* Time: 2014-04-07 11:22:09
*
* ZOJ 3768
* */
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <queue>
#include <set>
#include <vector>
using namespace std;

const int INF = ~0u>>1;
typedef pair <int,int> P;
#define MID(x,y) ((x+y)>>1)
#define iabs(x) ((x)>0?(x):-(x))
#define REP(i,a,b) for(int i=(a);i<(b);i++)
#define FOR(i,a,b) for(int i=(a);i<=(b);i++)
#define pb push_back
#define mp make_pair
#define print() cout<<"--------"<<endl

int check(int n){
int k = max(0,(int)sqrt(2 * n) - 4);
for (int i = k; i * i <= 2 * n; i ++){
if (i * i + i == 2 * n) return i;
}
return 0;
}

int main(){
int T,n;
cin >> T;
while (T--){
scanf("%d", &n);
int l,k = check(n);
if (k){
printf("%dn", k);
}else {
bool flag = 0;
for (int i = 1; i * i + i <= 2 * n; i ++){
l = check(n - (i + 1) * i /2);
if (l){
printf("%d %dn", i, l);
flag = 1;
break;
}
}
if (!flag){
for (int i = 1; i * i + i <= 2 * n && !flag; i ++){
int mod = n - (i + 1) * i / 2;
for (int j = 1; j * (j + 1) / 2 <= mod && !flag; j ++){
l = check(n - (j*(j+1)/2) - i * (i + 1) /2);
if (l){
printf("%d %d %dn", i, j ,l);
flag = 1;
break;
}
}
}
}
}
}
return 0;
}